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slega [8]
3 years ago
10

I add 3 odd numbers together to make 50 why am i incorrect

SAT
2 answers:
Kruka [31]3 years ago
8 0
You can never add odd numbers by an odd number of times to give you and even number. You can add an odd number and even number of times to give you an even number.
EX: 5 + 5 = 10      (5 is an odd number , but since you added it by an even number of times you get an even answer.)

aalyn [17]3 years ago
7 0
Adding odd numbers will only give you an even sum if the amount of numbers you added is an even number.

For example,
25 is an odd number. If you add 25, 2 times (2 is an even number) you will get 50 (an even number). If you add 25, 4 times (4 is an even number) you will get 100 (still, an even number)
However, if you add 25, 3 times (an odd number) you will get 75 (an odd number). If you add 25, 5 times (an odd number) you will get 125 (still an odd number).


Hopefully, that helped (: Sorry if I confused you lol

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Read 2 more answers
At 900 ∘c,kc=0. 0108 for the reaction caco3(s)←→cao(s)+co2(g) a mixture of caco3, cao, and co2 is placed in a 10. 0-l vessel at
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The concentration of CaCO3 increases in all cases because Q> K.

<h3>What is equilibrium?</h3>

A chemical reaction is said to have attained equilibrium when the rate of forward reaction is equal to the rate of reverse reaction. We are told that the Kc of the reaction is 0. 0108.

In the first case:

CaCO3 - 15.0 g/100g/mol/10 L = 0.015 M

CaO - 15.0 g/56 g/mol/10 L = 0.027 M

CO2 - 4.25 g/44 g/mol / 10 L = 0.0096 M

Q = [0.027] [0.0096]/0.015

Q = 0.017

Since Q > K, the concentration of CaCO3 increases

In the second case;

CaCO3 -  2.5 g/100g/mol/10 L =0.0025 M

CaO - 25.0 g/56 g/mol/10 L = 0.045 M

CO2 - 5.66 g/44 g/mol / 10 L = 0.013 M

Q = [0.045 ] [ 0.013]/[0.0025 ]

Q = 0.23

Q > K the concentration of CaCO3 increases

In the third case;

CaCO3 - 30.5 g/100g/mol/10 L =0.031 M

CaO - 25.5 g/56 g/mol/10 L =0.046 M

CO2 - 6.48 g//44 g/mol / 10 L = 0.015 M

Q = [0.046] [ 0.015]/[0.031]

Q = 0.022

Q> K hence the concentration of CaCO3 increases

Missing parts: At 900oC, Kc = 0.0108 for the reaction: CaCO3(s) <===> CaO(s) + CO2(g) A mixture of CaCO3, CaO, and CO2 is placed in a 10.0 Liter vessel at 900oC. For the following mixtures, will the amount of CaCO3 increase, decrease, or remain the same as the system approaches equilibrium? CaCO3 CaO CO2 At Equilibrium, CaCO3 will ?? 15.0 g 15.0 g 4.25 g Answer 2.5 g 25.0 g 5.66 g Answer 30.5 g 25.5 g 6.48 g Answer

Learn more about equilibrium: brainly.com/question/17960050

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