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Yakvenalex [24]
3 years ago
5

The resonance frequency f in an electronic circuit containing inductance L and capacitance C in series is given by f=1/2π√LC. De

termine the inductance L in an electric circuit if the resonance frequency is 6.2 and the capacitance is 0.0001. Round your answer to the nearest tenth.
10270.1
6.6
256.8
0
Mathematics
2 answers:
Nataly_w [17]3 years ago
7 0
For this case we have the following function:
 f = 1 / (2π√LC)
 Clearing L we have:
 √LC = 1 / (2πf)
 LC = (1 / (2πf)) ^ 2
 L = (1 / C) * (1 / (2πf)) ^ 2
 Substituting values:
 L = (1 / 0.0001) * (1 / (2 * 3.14 * 6.2)) ^ 2
 L = 6.596253438
 Round to the nearest tenth:
 L = 6.6
 Answer:
 
L = 6.6
sweet-ann [11.9K]3 years ago
3 0
In this situation, you have to use the equation
 f = 1 / (2π√LC)
 

To find L
 √LC = 1 / (2πf)
 LC = (1 / (2πf)) ^ 2
 L = (1 / C) * (1 / (2πf)) ^ 2

 Substitute the values:
 L = (1 / 0.0001) * (1 / (2 * 3.14 * 6.2)) ^ 2
 L = 6.596253438
 L = 6.6
So the  Answer is this:
 L = 6.6

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