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Contact [7]
3 years ago
9

melissa makes apple pies and sells them with a markup of 78%. write an equation representing the retail price y of melissa's app

le pies in terms of the original cost x.
Mathematics
2 answers:
Westkost [7]3 years ago
8 0

Answer:

Equation representing the retail price y of apple pies in terms of the original cost x  is      y = 1.78 x

Step-by-step explanation:

The original cost of apple pie = x

The mark up percentage = 78%

The retail price of the apple pie = y

Now, the mark up is always applied on the original price.

⇒78%  of x  = \frac{78}{100} \times x = 0.78x

So, the marked up amount of pie = 0.78 x

Also, the Total Retail price = Original Price + Marked up Price

                                             = x+ 0.78 x = (1+ 0.78)x  =  1.78 x

or, y = 1.78 x

Hence,equation representing the retail price y of apple pies in terms of the original cost x  is y = 1.78 x

Mandarinka [93]3 years ago
8 0

Answer:

x=y/1.78

Step-by-step explanation:

If you know the original value then you would multiply by 1.78 to calculate the price after markup. Thus if you know the price after markup you divide by 1.78 to find the original value.

y=markup price

x=original price

y=1.78x

Divide both sides by 1.78

y/1.78=x

x=y/1.78

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At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m
Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

  • Almost all the data lies within three standard deviation from the mean for a normally distributed data.
  • About 68% of data lies within one standard deviation from the mean.
  • About 95% of data lies within two standard deviations of the mean.
  • About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30

Thus, 99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

3 0
3 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

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kow [346]

17,190 / 5,730 = 3. This means we must divide 70mg in half 3 times

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35 / 2 = 17.5

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