Answer:
Density is defined as:
Density = mass/volume.
We know that:
For liquid A:
Density = 70kg/m^3
Mass = 1400kg
Then the volume is:
Volume = mass/density = (1400kg)/(70kg/m^3) = 20 m^3
For liquid B:
Density = 280 kg/m^3
Volume = 30m^3
We can find the mass of liquid B as:
mass = density*volume = (280kg/m^3)*(30m^3) = 8400 kg
We know that liquid C is a mixture of liquid A and B.
Then the mass of liquid C will be equal to the sum of the masses of liquid A and B, then:
Mass of liquid C = 1400kg + 8400kg = 9800kg
The same happens for the volume, then:
Volume of liquid C = 30m^3 + 20m^3 = 50m^3
Then the density of liquid C is:
Density of liquid C = (9800kg)/(50m^3) = 196 kg/m^3
Answer:
The answer is A(-3,-4) B(-1,2) C(2,1) D(0,-5)
Step-by-step explanation:
Answer:
After 2 seconds
Step-by-step explanation:
First step is find an equation of velocity:
h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.
v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.
Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.
0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ 
=
t=2. That means after 2 sec. the arrow reach the maximum height
Step-by-step explanation:
<u>Combine Like-Terms:</u>
-0.8m + 3 - 12.5m + 95.36m
-13.3m + 3 + 95.36m
82.06m + 3
82.06m + 3 is your simplified expression.
Need approx 3 oz chemical to 1 gal water.
Conversion factor is then approx. 3 oz
---------
1 gal
Mult this result by 6 gal. This gives you 18 oz, approx.
Now let's look for a more exact solution:
2.75 oz 19 gal
---------- * ---------- = 17.4 oz. The 18 oz estimate was close.
1 gal 3
