Answer:
For a geometric sequence with recurrence of the form a(n)=ra(n-1) where r is constant, each term is r times the previous term. This implies that to get from the first term to the nth term, we need to multiply by n-1 factors of r.
Step-by-step explanation:
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you are looking so h*t and s**y..
Answer:
Step-by-step explanation:
Let first odd number = a, second odd number = a +2, third odd number = a + 4
a + a + 2 + a + 4 = 987
3a + 6 = 987
3a = 981
a = 327
First odd number = a = 327
Second odd number = a + 2 = 329
Third odd number = a + 4 = 331
I believe the correct answer is true. <span>When solving a system of linear equations, try to algebraically form one equation that has only one variable. In this way, you can solve the value of that variable and eventually solve the other variables. Hope this answers the question. Have a nice day.</span>
Answer:
Yes
Step-by-step explanation:
