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3 years ago

The weights of bags of pet food are distributed normally about the mean, 50 lb. the standard deviation is 0.2 lb.

Mathematics

1 answer:

saveliy_v [14]3 years ago

5 0

$20 - 50 \div .2$
I assume take the z score or it would be about 30% because of the 60, 95, 97.5 rule which has a technical name that I can't remember

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Stuart paid $ 48.00 for a New tennis racket ,which was 64% of the original price what was the original price of the racket.

Trava [24]

Seventy five dollars hope this could help[

5 0

3 years ago

Solve the inequality 9/2 + v > 7/5

statuscvo [17]

Answer:

the answer is -31/20

Step-by-step explanation:

4 0

2 years ago

If a spinner for a game is spun once, there is a 25% chance it will land on

bonufazy [111]

Answer:

$Pr = 0.6$

Step-by-step explanation:

Given

Let

$O \to Orange$

So:

$P(O) = 25\%$ --- probability of O

$n=2$ --- Number of spin

Using the complement rule, the probability that a spin will not land on orange is:

$P(O') = 1 - P(O)$

$P(O') = 1 - 25\%$

Express as decimal

$P(O') = 1 - 0.25$

$P(O') = 0.75$

On two spins, the probability that it will not land on orange is:

$Pr = P(O') * P(O')$

So, we have:

$Pr = 0.75* 0.75$

$Pr = 0.5625$

$Pr = 0.6$ --- approximated

6 0

2 years ago

Please help me on this problem

Orlov [11]

Answer:

The Proof with Figure, Statement and Reasons is given below.

Step-by-step explanation:

Given:

∠DAF ≅ ∠EBF,

DF ≅ FE

Prove:

Δ ADF ≅ Δ BFE

Proof:

Statements Reasons

a. ∠DAF ≅ ∠EBF ...........................Given

48. ∠DFA ≅ ∠EFB ..........................Vertical Angles are congruent

DF ≅ FE ...........................49. Given

50. Δ ADF ≅ Δ BFE .........................By Angle-Angle-Side test

6 0

3 years ago

You decide to play roulette 200 times each time betting the same amount on red. you will loe money if you win on fewer than 100

Arturiano [62]

First off, your chances of red are not really 50-50. You are overlooking the 0 slot or the 00 slot which are green. So, chances of red are 18 in 37 (0 slot) or 38 (0 and 00 slots). With a betting machine, the odds does not change no trouble what has occurred before. Think through the simplest circumstance, a coin toss. If I toss heads 10 times one after the other, the chances of tails about to happen on the next toss are still on a 50-50. A betting machine has no ability, no plan, and no past.
Chances (0 slot) that you success on red are 18 out of 37 (18 red slots), but likelihoods of losing are 19 out of 37 (18 black plus 0). For the wheel with both a 0 and 0-0 slot, the odds are poorer. You chances of red are 18 out of 38 (18 red slots win), and down are 20 out of 38 (18 black plus 0 and 00). It does not really matter on how long you play there, the probabilities would always continue the same on every spin. The lengthier you play, the more thoroughly you will tie the chances with a total net loss of that portion of a percent in accord of the house. 18 winning red slots and either 19 or 20 losing slots.

6 0

3 years ago