Answer: -7920
Step-by-step explanation: 33x-6x40= -7920
If you are rounding it will be the same thing
Answer:
(a)$67
(b)You are expected to win 56 Times
(c)You are expected to lose 44 Times
Step-by-step explanation:
The sample space for the event of rolling two dice is presented below

Total number of outcomes =36
The event of rolling a 5 or a 6 are:

Number of outcomes =20
Therefore:
P(rolling a 5 or a 6) 
The probability distribution of this event is given as follows.

First, we determine the expected Value of this event.
Expected Value

Therefore, if the game is played 100 times,
Expected Profit =$0.67 X 100 =$67
If you play the game 100 times, you can expect to win $67.
(b)
Probability of Winning 
If the game is played 100 times
Number of times expected to win

Therefore, number of times expected to loose
= 100-56
=44 times
Answer: <em>1/10</em>
Step-by-step explanation: These two events are independent, meaning the outcome of the first event doesn't affect the outcome of the second.
To find the probability of independent events, first, find the
probability of each event, then multiplies the probabilities.
The probability of spinning an A on the first spinner is 1/5
since there is 1 favorable outcome and 5 total outcomes.
The probability of spinning an odd number on the second spinner
is 3/6 which simplifies to 1/2 since there are 3 favorable outcomes,
spinning a 1, 3, or another 3 since these are odd numbers.
So now we have 1/5 × 1/2 and when multiplying fractions,
we multiply across the numerators and denominators to get 1/10.
So the probability of spinning an A, then an odd number is 1/10.