Answer:
the probability that 11 adults are satisfied is 0.115 (11.5%)
Step-by-step explanation:
since the result of each adult is independent of others , then since the adults are selected at random , the random variable X= number of adults who are satisfied , has a binomial probability distribution , where
P(X=x) = n!/[(n-x)!*x!] * p^x * (1-p)^(n-x)
where
n= sample size = 20
p= probability of any adult to be satisfied with the job of airlines = 0.65
x = number of adults who are satisfied
P(X=x) = probability that x adults are satisfied
then for x= 11 , we have
P(X=11) = 20!/[(20-11)!*11!] * 0.65^11 * (1-0.65)^(20-11) = 0.115 (11.5%)
then the probability that 11 adults are satisfied is 0.115 (11.5%)
