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Ray Of Light [21]
3 years ago
8

A point, beginning at (0,0), undergoes the following composition of translation. Write an ordered pair for the points final posi

tion. T<5,-7> and then T<-6,2>

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0

Answer:

(-1,-5)

Step-by-step explanation:

Starting at (0,0), we perform the first translation:

T<5,-7> implies that we move the point 5 units to the right (in the x (horizontal) direction), and 7 units DOWN in the y <vertical) direction.

From there we do the second translation: T<-6,2>

which means: 6 units to the left (in the horizontal direction) which takes us to  "-1" for the x value, and 2 units up (vertical) which takes us to -5 for the y value.

Therefore the new location is (-1,-5)

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What is the slope of the line that passes through the points (-4, -9) and (5, 3)
egoroff_w [7]

Answer:

4/3

Step-by-step explanation:

Moving from (-4, -9) to (5, 3), x (the 'run') increases by 9 from -4 to 5, and y (the 'rise') increases by 12 from -9 to +3.  Thus, the slope of the line connecting the two points is

m = rise / run = 12/9 = 4/3

It may help to think of the change in x (9) as the horizontal leg of a right triangle and the change in y (12) as the vertical leg.  Then  

m = (vertical leg length) / (horizontal leg length) = 12/9 = 4/3

5 0
2 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
-BARSIC- [3]

The inequality \mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }} gives the least number of buses, b, needed for the trip. The least number of buses is 9

<u>Solution:</u>

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.  

Each bus can seat a maximum of 48.  

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

<em><u>The number of buses required “b” is given as:</u></em>

\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}

\text { So, number of buses required } \geq \frac{432}{48}

Number of buses required ≥  9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality \mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}} gives least count of busses and least count is 9.

6 0
3 years ago
Find the area of the figure
Anna71 [15]

Answer: 52x+4

Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.

5 0
3 years ago
Which of the following is not an example of like terms? A. 2 and –6 B. 2b and –6b C. 2b and 2
Serggg [28]
I think it would be c
7 0
3 years ago
Read 2 more answers
your school sold 456 tickets for a high school play. An adult ticket cost $3.50. A student ticket cost $1. Total to ket sales eq
Svet_ta [14]
A + s = 456........a = 456 - s
3.5a + s = 1131

3.5(456 - s) + s = 1131
1596 - 3.5s + s = 1131
-3.5s + s = 1131 - 1596
-2.5s = - 465
s = -465/-2.5
s = 186 <====== student tickets sold

a + s = 456
a + 186 = 456
a = 456 - 186
a = 270 <==== adult tickets sold
7 0
3 years ago
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