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lilavasa [31]
3 years ago
11

2x+y=11 4x-3y=7 substitution

Mathematics
2 answers:
3241004551 [841]3 years ago
4 0
Solve for y in the first equation.

y=-2x+11

Plug it into the second equation.

4x-3(-2x+11)=7
4x+6x-33=7
10x=40
x=4

Plug the x value into one of the original equations,

2(4)+y=11
8+y=11
y=3

Final answer: (4,3)
notka56 [123]3 years ago
3 0
2x+y=11. 2x=11-y. X=11/2-y/2 x=11-y
2
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Examine the following graph, where the function P(x) is mapped to I(x) by a translation.
Murrr4er [49]

f(x) = p(x) + 4 shows the correct transformation.

<h3>Define transformations.</h3>

A point, line, or geometric figure can be transformed in one of four ways, each of which affects the shape and/or location of the object. Pre-Image refers to the object's initial shape, and Image, after transformation, refers to the object's ultimate shape and location. The most typical varieties are listed below: When a figure is translated, it is moved in any direction. Flipping a figure over a line is called reflection. Rotation is the process of turning a figure a specific amount around a point.

Given,

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f(x) = p(x) + 4

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6 0
1 year ago
12x+15y=-45 put into slope-intercept form, simplify all fractions.
Karo-lina-s [1.5K]

Answer:

y = -4/5 x - 3

Step-by-step explanation:

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7 0
2 years ago
A square poster has a side length of 26 in. Drawn on the poster are four identical triangles. Each triangle has a base of 8 in.
Firdavs [7]
To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.

Divide the area of the combined areas and the total area to find the probability of landing on a triangle.

A = 1/2bh
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A = 32 square inches
32 x 4
128 square inches (areas of triangles)

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6 0
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Answer:

I dont know if this helps

5 0
3 years ago
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PLZ HELP ME I NEED THIS ASAP
Andru [333]

Mean = 110

Sample size = 45

Standard deviation = 6

Z score for 90% is 1.645 ( from Z-table).

Lower Limit = Mean - Z(SD/√Sample size))

Lower limit = 110 - 1.645(6/√45)

Lower limit = 108.5

Upper Limit = Mean + Z(SD/√Sample size))

Lower limit = 110 +1.645(6/√45)

Lower limit = 111.5

The interval is (108.5, 111.5)

3 0
3 years ago
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