All categories

3 years ago

Without finding the inverse of the function determine the range of the inverse of F(x) = the square root of x-4

1 answer:

3 0

The rang of an inverse function is the domain of the normal function
So you just gotta find the domain of that which is x is greater than or equal to 0

You might be interested in

3x 48 x+32 solve for x

gtnhenbr [62]

Answer:

51x+32

Step-by-step explanation:

combine like terms

3x+48x=51x

since 32 is alone it just stays alone

51x+32

hope this helps

4 0

4 years ago

Plese help me fast I will mark you brainlist

Alona [7]

Answer:

x= 70 y= 70

Step-by-step explanation:

8 0

3 years ago

Need help with this trigonometry word problem

fenix001 [56]

Answer:

$\huge \boxed{ \boxed{ \sf 6\sqrt{3} \: or \: 10.4}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

trigonometry
PEMDAS

<h3>let's solve:</h3>

to find <u>how far the ladder is from the foot of the </u><u>wall </u>

we will use tan function because we are given opposite and angle

we need to find adjacent

$\quad \tan( \theta) = \dfrac{opp} {adj}$

let adjacent be BC

$\boxed{ \red{ \boxed{accoding \: to \: the \: question : }}}$

$\quad \: \tan( {60}^{ \circ} ) = \dfrac{6}{BC}$

we will use a little bit algebra to figure out BC

$\sf substitute \: the \: value \: of \: \tan( {60}^{ \circ} ) \: i.e \: \sqrt{3} : \\ \sqrt{3} = \frac{BC}{6}$
$\sf cross \: multiplication : \\ \therefore \: BC = 6\sqrt{3} \: or \: 10.4$

$\text{And we are done!}$

7 0

3 years ago

Read 2 more answers

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

4 years ago

The bases of a trapezoid are 16.8 yards and 6.9 yards. If the height is 2 yards, what is the area of the trapezoid?

Svet_ta [14]

Hello,
Here is the formula to find the area of the trapezoid:
A=1/2(b1+b2)×h
Where b1 represent big base
b2 represent small base
and h represent height
Now, we just need to replace the number to get the final answer:
A=1/2(16.8+6.9)×2
A=1/2(23.7)×2
A=23.7 square yards. As a result, the area of the trapezoid is 23.7 square yards. Hope it help!

8 0

4 years ago