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fomenos
3 years ago
15

The roof has a vertical height of 8 feet. The house has a width of 20

Mathematics
2 answers:
icang [17]3 years ago
6 0

Answer: 1740?

Step-by-step explanation:

I just added and multiplied

Vadim26 [7]3 years ago
3 0
I think the answer is 1740 but i might be wrong
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the student council wants to raise at least $500. Students must pay $2 to attend. How many student will need to attend in order
dezoksy [38]

Answer:

250 students at a minimum must attend to meet the student council goal.

Step-by-step explanation:

divide 500 by 2. you get 250 students that pay $2 each that equals $500.

6 0
3 years ago
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Trevor paid a total of $1.08 in fines for an overdue library book. If the penalty for overdue books is $0.09 per day, how many d
WARRIOR [948]

Answer:

12

Step-by-step explanation:

1.08 1.08 divded by 0.09 equals 12

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2 years ago
HELP WILL GIVE BRAINLEIST
TiliK225 [7]

Answer:

2x+y=

1 beacuse ...... i had the same question

Step-by-step explanation:

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Mrs. Merritt, has 75% of her $300 dollar goal, how much money does she have?
Triss [41]

Answer:

She has 225 dollars

Step-by-step explanation:

75% of her $300

Change the percent to decimal form

.75 * 300

225

She has 225 dollars

3 0
2 years ago
Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Round answers to three decimal places.
zlopas [31]

Answer:

a) x= arccos(3/5) = 0.927

Just one solution

b) cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c) x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d) x= -0.1145

Step-by-step explanation:

a. 5 cos(x) − 3 = 0

For this case we can do this:

5 cos(x) = 3

Now we can divide both sides by 5 and we got:

cos (x) = \frac{3}{5}

If we apply arccos on both sides we got:

x = arccos (\frac{3}{5})+2\pi n, x=2\pi-arccos (\frac{3}{5})+2\pi n

So for this case the possible solution is:

x= arccos(3/5) = 0.927

Just one solution. This is only the solution on the interval assumed.

b. 3 cos(x) + 5 = 0

We can do this:

3 cos (x) = -5

Then we can divide by 3 both sides and we got:

cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c. 3 sin(x) − 1 = 0

We can do this:

3 sin(x) = 1

Then we can divide both sides by 3 and we got:

sin(x) = \frac{1}{3}

The general solutions would be:

x = arcsin(\frac{1}{3}) + 2\pi n , x= \pi -arcsin (\frac{1}{3}) + 2\pi n

x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d. tan(x) = −0.115

For this case we can solve the value of x like this:

x = arctan(-0.115) +\pi n

And then the only possible solution for this case is:

x= -0.1145

3 0
3 years ago
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