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Amanda [17]
3 years ago
5

Write the quadratic equation y=x^2-6+7 in vertex form

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0
Half the x-coefficient is -3, so the equation needs to be rearranged into a form that looks like
  x² -6x +(-3)² + [something]
You can get there by adding and subtracting 9 from the original equation.
  y = x² -6x +9 +7 -9 . . . . . 9 added and subtracted
  y = (x² -6x +9) -2
The quantity in parentheses is a perfect square, so we can write the equation in the desired form as ...
  y = (x -3)² -2
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Answer:

<h2>39.27 cm²</h2><h2 />

Step-by-step explanation:

area of semi circle = π r² / 2

where r = 10/2 = 5 cm

area = π (5)² / 2

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Paladinen [302]
1.) 20,24,25,27,31,35,38
2.) Least value: 20 Greatest value: 38 Median: 27
3.) Lower Quartile: 24 Upper Quartile: 35
4.) Draw the first dot above 20, then a line connecting to the first line above 24, then another line above 27, then another line above the 35, then connect it to the dot that will be above 38. The lines above 24, 27,35 should make a box like the one shown at the beginning of your paper.
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3 years ago
PLEASE help me with this question! No nonsense answers and answer with full solutions please!
ohaa [14]

Answer:  b) {-3, 0.5}

Step-by-step explanation:

The new equation is the original equation plus 6.  Move the original graph UP 6 units.  The solutions are where it crosses the x-axis.

\text{Original equation:}\quad f(x)=\dfrac{15}{x}-\dfrac{9}{x^2}\\\\\\\text{New equation:}\quad\dfrac{15}{x}+6=\dfrac{9}{x^2}\\\\\\.\qquad \qquad  f(x)= \dfrac{15}{x}-\dfrac{9}{x^2}+6

+6 means it is a transformation UP 6 units.  

Solutions are where it crosses the x-axis.

The curve now crosses the x-axis at x = -3 and x = 0.5.

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