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Amanda [17]
3 years ago
5

Write the quadratic equation y=x^2-6+7 in vertex form

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0
Half the x-coefficient is -3, so the equation needs to be rearranged into a form that looks like
  x² -6x +(-3)² + [something]
You can get there by adding and subtracting 9 from the original equation.
  y = x² -6x +9 +7 -9 . . . . . 9 added and subtracted
  y = (x² -6x +9) -2
The quantity in parentheses is a perfect square, so we can write the equation in the desired form as ...
  y = (x -3)² -2
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Answer:

2.

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Hope this helps

Step-by-step explanation:

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2 years ago
What is the solution to the system of linear equations?
Dmitry_Shevchenko [17]

Answer:

x = 5, y = -1/2

Step-by-step explanation:

3.5x - 5y = 20

3x + 4y = 13 multiply by 1.25 so the y's match up (you could match x's too)

3.75x + 5y = 16.25

–––––––––––––––––––––––

3.5x - 5y = 20

3.75x +5y = 16.25

7.25x + 0y = 36.25 you can add or subtract here (on this equation you add)

7.25x=36.25

x=5 So now we have x=5 and to find y we can just plug in x into one of the equations

–––––––––––––––––––

3(5) + 4y = 13

15 + 4y = 13

4y = -2

y = -1/2

x = 5, y = -1/2

Then you can plug in both to check your answers.

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alined, hope this helps

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