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BlackZzzverrR [31]
3 years ago
15

I'd really appreciate it if you'd help! :)

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

The answer to your question is

h=2y+36

why?

because he was already 36 inches which mean he would be adding on the inches.

So he would grow 2 inches a year plus the 36 inches he already was.


Hope this helps

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Determine the rate of change for 6y=8x-40
Maksim231197 [3]
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hich of the following expressions is equivalent to |x + 4| < 5? A. –5 > x + 4 < 5 B. –5 < x + 4 < 5 C. x + 4 <
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Answer:

option B

Given : |x + 4| < 5

A. –5 > x + 4 < 5

B. –5 < x + 4 < 5

C. x + 4 < 5 and x + 4 < –5

D. x + 4 < 5 or x + 4 < –5

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Then we translate to -n < x < n

|x + 4| < 5

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5 0
3 years ago
Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =
vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2

a_1=8

Find the value of a_2

For n=2

a_2=2.9(a_1)-0.2(a_1)^2

a_2=2.9(8)-0.2(8)^2=10.4

Find the value of a_3

For n=3

a_3=2.9(a_2)-0.2(a_2)^2

a_3=2.9(10.4)-0.2(10.4)^2=8.528

For n=4

a_4=2.9(a_3)-0.2(a_3)^2

a_4=2.9(8.528)-0.2(8.528)^2=10.1858

For n=5

a_5=2.9(a_4)-0.2(a_4)^2

a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887

therefore

The population alternates between increasing and decreasing

7 0
3 years ago
Read 2 more answers
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