For the coefficients to be rational, any complex roots must occur in conjugate pairs. So if
is a root, then so must be
.
Now such a third degree polynomial might be
The only variation to this would be multiplying throughout by some non-zero constant. This doesn't change the roots.
Answer:
x=2 and y=1
Step-by-step explanation:
if y is 1 then u can multiply the three and 4 which is the same and then add 2 which add up to 5 and 6
Answer:
see explanation
Step-by-step explanation:
The n th term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given
6(a₁ + 5d) = 13(a₁ + 12d) ← distribute parenthesis on both sides
6a₁ + 30d = 13a₁ + 156d ( subtract 13a₁ from both sides )
- 7a₁ + 30d = 156d ( subtract 30d from both sides )
- 7a₁ = 126d ( divide both sides by - 7 )
a₁ = - 18d
Now
a₁₉ = a₁ + 18d = - 18d + 18d = 0 ← as required
Answer:
x=-25/2
Step-by-step explanation:
Answer:
midpoint equation
Step-by-step explanation:
