The answer is Class A. The GFCI (Ground Fault Circuit Interrupter) will “sense” the difference in the
amount of electricity flowing into the circuit to that flowing out, even in
amounts of current as small as 4 or 5 milliamps. The GFCI reacts
quickly (less than one-tenth of a second) to trip or shut off the circuit.
Using the knowledge of computational language in JAVA it is possible to write a code that Fixing syntax errors Click run to compile, and note the long error list.
<h3>Writting the code:</h3>
<em>public class BeansInJars {</em>
<em> public static void main(String[] args) {</em>
<em> int numBeans;</em>
<em> int numJars;</em>
<em> int totalBeans;</em>
<em> numBeans = 500;</em>
<em> numJars = 3;</em>
<em> System.out.print(numBeans + " beans in ");</em>
<em> System.out.print(numJars + " jars yields ");</em>
<em> totalBeans = numBeans * numJars;</em>
<em> System.out.println(totalBeans + " total");</em>
<em> }</em>
<em>}</em>
See more about JAVA at brainly.com/question/12975450
#SPJ1
Answer:
The solution code is written in C++
- void BigInt(int n){
-
- int i, j;
-
- for(i = 1; i <= n; i++){
-
- for(j = 1; j <= i; j++){
-
- if(j < 10){
-
- cout<<j;
- }
- else{
- cout<<0;
- }
-
- }
-
- cout<<"\n";
-
- }
- }
- int main()
- {
- BigInt(10);
-
- return 0;
- }
Explanation:
Firstly, create a function BigInt that takes one input number, n.
Next, create a double layer for-loop (Line 5-21). The outer loop is to print one big number per iteration and the inner layer is keep printing the accumulated individual digit for a big number. To ensure the big number is printed one below the other, we print a new line in outer loop (Line 19).
In main program, we call the function to print the big number (Line 26).