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HACTEHA [7]
3 years ago
6

What is Microsoft first product

Computers and Technology
2 answers:
Alenkasestr [34]3 years ago
3 0

Answer:  Xenix

Explanation:

Rashid [163]3 years ago
3 0

Answer:

Xenix-used as a word processing tool.

Explanation:

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Does any one here play destiny on xbox one
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WILL GIVEE BRAINLIEST ANSWER!!!!
Licemer1 [7]

Answer:

People have been ringing the death knell for email on and off for a few years now. But should we be listening?

The latest peal came from French IT company Atos, which declared that it would phase out internal emails by 2013. And for reasons we’ll all recongize: too much time spent dealing with too many emails, of which too few are useful and too many are spam. CEO Thierry Breton said his staff would instead use good old face-to-face communication, as well as instant messaging (IM) and social media tools.

3 0
3 years ago
Write a program with a function that accepts a string as an argument and returns the number of uppercase, lowercase, vowel, cons
diamong [38]

Answer:

Explanation:

The following code is written in Python. It is a function called checkString that takes in a string as an argument and loops through each char in that string and checking to see if it is lowercase, uppercase, vowel, consonant, or punctuations. It adds 1 to the correct variable. At the end of the loop it prints out all of the variables. The picture below shows a test output with the string "Brainly, Question."

def checkString(word):

   uppercase = 0

   lowercase = 0

   vowel = 0

   consonants = 0

   punctuation = 0

   vowelArray = ['a', 'e', 'i', 'o','u', 'y' ]

   consonantArray = ['b', 'c', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'm', 'n', 'p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z']

   punctuationArray = ['.', '!', '?', ',', ';', '(', ')']

   for char in word:

       if char.isupper():

           uppercase += 1

       else:

           lowercase += 1

       if char.lower() in vowelArray:

           vowel += 1

       elif char.lower() in consonantArray:

           consonants += 1

       if char in punctuationArray:

           punctuation += 1

   print('Uppercase: ' + str(uppercase))

   print('Lowercase: ' + str(lowercase))

   print('Vowels: ' + str(vowel))

   print('Consonants: ' + str(consonants))

   print('Punctuations: ' + str(punctuation))

8 0
3 years ago
Programming in https<br>​
kakasveta [241]
What?? explain your question
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3 years ago
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