Answer:
Mean $1060
Standard error $34.69
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation, which is also called standard error,
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Population:
Mean $1,060 and standard deviation $190.
Sampling distriution of samples of size 30:
Mean $1060
Standard deviation ![s = \frac{190}{\sqrt{30}} = 34.69](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B190%7D%7B%5Csqrt%7B30%7D%7D%20%3D%2034.69)
It’s the 3rd answer trust me