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Verdich [7]
3 years ago
6

Is 17/31 greater than 19/14

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

No

Step-by-step explanation:

Put both in your calculator. Do it in this order.

17

÷

31

=

0.5484

=========

Now do the next one

18

÷

14

=

1.357

19/14 > 17/31

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7 0
3 years ago
Which of the following is a proportional relationship?
Solnce55 [7]

The two equations represent the proportional relationship.

y=3x and y=12x are proportional relation ship equations

proportion equations can be defined as

If we change x the y will change in the same proportion.

<h3>What is the proportional relationship?</h3>

Proportional relationships are relationships between two variables where their ratios are equivalent.

Another way to think about them is that, in a proportional relationship, one variable is always a constant value time the other.

That constant is known as the constant of proportionality.

proportional relationship equation contain (0,0) points

If we put x=0

This  will give us,y=0

If we put x=0, in y=12x

It will give y=0

put if we put x=0 in

y=3x it will give us y=0

hence these two equations represent the proportional relationship.

To learn more about the equation visit:

brainly.com/question/2972832

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6 0
2 years ago
Colin pays £766.45 a year on his car insurance.
Firlakuza [10]

Answer:

£807.8383

Step-by-step explanation:

100 plus 5.4= 1.054%

1.054 x £766.45=£807.8383

7 0
3 years ago
Is this right? ASAP PLS HURRY!
Oksanka [162]
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3 0
2 years ago
Make n the subject of the formula
kogti [31]

Answer:

\mathsf{ \frac{m + 21}{5} = n }

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

  • <em>there's</em><em> </em><em>a</em><em> </em><em>"</em><em>-21</em><em>"</em><em> </em><em>next</em><em> </em><em>to</em><em> </em><em>"</em><em>5n</em><em>"</em><em>,</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>subtraction</em><em> </em><em>is</em><em> </em><em>addition</em><em>,</em><em> </em><em>so</em><em> </em><em>add</em><em> </em><em>21</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>.</em><em> </em>

=> m + 21 = 5n <u>-</u> <u>21</u> + <u>21</u>

=> m+ 21 = 5n

  • <em>There's</em><em> </em><em>also</em><em> </em><em>a</em><em> </em><em>5</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>n</em><em>,</em><em> </em><em>that</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>multiplication</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>with</em><em> </em><em>5</em><em>,</em><em> </em><em>the</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>multiplication</em><em> </em><em>is</em><em> </em><em>division</em><em>,</em><em> </em><em>so</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>5</em>

<em>\mathsf{ \frac{m + 21}{5} = n }</em>

3 0
3 years ago
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