Answer:
B. about 76 in 2
Step-by-step explanation:
The picture of the question in the attached figure
I will assume that the tile is a regular hexagon
The area of the regular hexagon is equal to the area of six congruent equilateral triangles
Applying the law of sines to calculate the area of triangle
Remember that the measure of the interior angle in a equilateral triangle is 60 degrees
so
![A=6[\frac{1}{2} b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%20b%5E2sin%2860%5Eo%29%5D)

substitute
![A=6[\frac{1}{2} (5.4)^2sin(60^o)]=75.76\ in^2](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%20%285.4%29%5E2sin%2860%5Eo%29%5D%3D75.76%5C%20in%5E2)
therefore
The area of each tile is about 76 square inches
Answer:
i am sure its the length of two sides
Answer: OPTION A
Step-by-step explanation:
To simplify the expression you must multiply the numerator and the denominator of the expression by √3.
As all the square roots have equal index, you can multiply the radicands, which are the numbers inside of the sqaures roots.
You also must keep on mind that:
![(\sqrt[n]{a})^n=a](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Ba%7D%29%5En%3Da)
Therefore, you obtain:
![\frac{6\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}=\frac{6\sqrt[]{6}}{3}=\frac{2\sqrt[]{6}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B6%5Csqrt%7B2%7D%2A%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%2A%5Csqrt%7B3%7D%7D%3D%5Cfrac%7B6%5Csqrt%5B%5D%7B6%7D%7D%7B3%7D%3D%5Cfrac%7B2%5Csqrt%5B%5D%7B6%7D%7D%7B3%7D)
Answer:
Might be wrong but 27. Hope this helps
(1/8) / (3/4) =
1/8 * 4/3 =
4/24 reduces to 1/6 <===