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Nadusha1986 [10]
3 years ago
10

A slot machine has 3 dials. Each dial has 30 positions, one of which is "Jackpot". To win the jackpot, all three dials must be i

n the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?
1/30 = 0.03 or 3%


3/(30+30+30) = 3/90 = 0.33 or 33%


3/(30×30×30) = 3/27000 = 0.0001 or 0.01%


1/(30×30×30) = 1/27000 = 0.00003 or 0.003%
Mathematics
2 answers:
givi [52]3 years ago
5 0

Answer:

here we have 3 dials in the slot machines and each dial has 30 position

so probability of getting a number of the each dial   =  

30

1

​

 

since all dials are independent so probability of getting same number would be

P ( getting jack pot) =  

30

1

​

 

30

1

​

 

30

1

​

   =    

27000

1

​

   = 0.003% option D is correct.

Step-by-step explanation:

Lostsunrise [7]3 years ago
3 0

Answer:

3/(30×30×30) = 3/27000 = 0.0001 or 0.01%

Step-by-step explanation:

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