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damaskus [11]
3 years ago
8

Please help! 3 questions, 1. Determine if the ordered pair is a solution of the equation. Is (-1,-30) a solution of y =10x?: a)

True b) False
2.The point (5, -1) is a solution of the equation: y = 2x − 11 options: a) True b) False 3.Which ordered pairs are a solution to the equation? y = 8x options: a) (-1,-7) b) (2,16) c) (1,8) d) (-2,-6)
Mathematics
1 answer:
ladessa [460]3 years ago
8 0
This is just a matter of subbing and solving to see if the equations are true

(-1,-30)...x = -1 and y = -30
y = 10x...so we sub
-30 = 10(-1)
-30 = -10 (incorrect)...so this is not a solution
================
(5,-1)...x = 5 and y = -1
y = 2x - 11
sub
-1 = 2(5) - 11
-1 = 10 - 11
-1 = -1 (correct)....so this is a solution
==============
y = 8x
sub in (2,16)...x = 2 and y = 16
16 = 8(2)
16 = 16 (correct)...so (2,16) is a solution

y = 8x
subbing in (1,8)...x = 1 and y = 8
8 = 8(1)
8 = 8 (correct)...so (1,8) is also a solution

thats all...just those 2 are the solutions
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7 0
3 years ago
Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu
Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

  • Cada manzana cuesta $3.
  • Cada pera cuesta $1.

-----------------------

  • Un sistema de ecuaciones soluciona esta pergunta.
  • El custo de una manzana es x.
  • El custo de una pera es y.

-----------------------

  • <u>Seis manzanas y 8 peras cuestan $26</u>, o sea, 6x + 8y = 26
  • <u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

6x + 8y = 26

6(3y) + 8y = 26

18y + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y = 3(1) = 3.

Cada manzana cuesta $3.

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