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Helen [10]
2 years ago
11

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

e cuesta cada pera?
Mathematics
1 answer:
Rom4ik [11]2 years ago
6 0

Usando un sistema de ecuaciones, se encuentra que

  • Cada manzana cuesta $3.
  • Cada pera cuesta $1.

-----------------------

  • Un sistema de ecuaciones soluciona esta pergunta.
  • El custo de una manzana es x.
  • El custo de una pera es y.

-----------------------

  • <u>Seis manzanas y 8 peras cuestan $26</u>, o sea, 6x + 8y = 26
  • <u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

6x + 8y = 26

6(3y) + 8y = 26

18y + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y = 3(1) = 3.

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

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Let us assume the number of vegetarian wraps made = x
Let us assume the number of chicken wraps made = y
Then
x + y = 70
x = 70 - y
And
x + 1.80y = 98.80
Putting the value of x from the first equation in the second equation, we get
x + 1.80y = 98.80
70 - y + 1.80y = 98.80
0.80y = 28.80
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Putting the value of y in the first equation, we get
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From the above deduction, we can conclude that the number of vegetarian warps sold was 34. I hope the answer has come to your desired help.
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Step-by-step explanation:

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Sharon spent $3.45 on sunflower seeds. The price of the sunflower seeds is $0.89 per pound. How many pounds of sunflower seeds d
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I literally don’t get none of this
faust18 [17]

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Angle 5, 4, and 7.

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Angle 2 is vertical to angle 5, making them congruent.


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A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq
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Answer:

7.8655

Step-by-step explanation:

Given the functionl

U=Ax^3+Bx^2-cx+D

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A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J

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U=1.45x^3+2.85x^2-1.7x+0.6

We need to derivate and verify for stable equilibrum that,

\frac{d^2 U}{dx^2}>0

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x_1=-1.57008\\x_2=0.250636

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