All categories

3 years ago

Jamal scored 62, 75, 76, and 90 on four tests. What does he need to score on the

Mathematics

1 answer:

Irina18 [472]3 years ago

3 0

Answer:

Step-by-step explanation:

In order to find the next score that he needs to get, add all of the previous four scores: 62+75+76+90 = 303. Then multiply 80 and 5 = 400. Subtract 400 and 303 = 97

You might be interested in

7z2 5z4 d3 d8<br> I don't know how you are supposed to do it?

Serga [27]

Answer:

$35 {z}^{6} {d}^{11}$

Step-by-step explanation:

Assuming you are supposed to simplify:

$7 {z}^{2} \times 5 {z}^{4} \times {d}^{3} \times {d}^{8}$

Then we need to apply the product rule of indices.

${a}^{m} \times {a}^{n} = {a}^{m + n}$

So we multiply to get:

$35 {z}^{2 + 4} \times {d}^{3 + 8}$

We now simplify the exponents to get:

$35 {z}^{6} \times {d}^{11}$

Therefore the required product is

$35 {z}^{6} {d}^{11}$

3 0

3 years ago

The Vertex is the part of a quadratic equation where the graph changes_________?

Georgia [21]

I think it slopeeeeeeeeeeeeeeeeeeee

8 0

3 years ago

Read 2 more answers

HELP?? A lunch combo has the following options: Entree: Hamburger, Hotdog, Chicken sandwich Side: Apples, Salad Drink: Milk, Wat

murzikaleks [220]

Using the Fundamental Counting Theorem, the sample size of these outcomes is of 12.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

Considering the number of options for Entree, Side and Drink, the parameters are:

n1 = 3, n2 = 2, n3 = 2.

Hence the sample size of outcomes is:

N = 3 x 2 x 2 = 12.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

3 0

2 years ago

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form.

Paladinen [302]

Answer:

gradient =y2-y1÷x2-x1

=10-5÷2-(-3)

y-y1=m(x-x1)

y-5=1(x-(-3))

y=x+2

7 0

3 years ago

What is the answer for this one ??

Arisa [49]

Answer: D

Step-by-step explanation:

A. 3 + -7 < -4

-4 < -4

this one isn’t a solution

B. 3 + -7 ≤ -4

-4 ≤ -4

this works, let’s try the other equation

3(3) + 2(-7) < -5

9 + -14 < -5

-5 < -5

this one doesn’t work either, let’s go on to the next one

C. the first equation is the same as the first one in A, and that didn’t work, so we know that the whole thing doesn’t work and we don’t have to do any math

D. we know the first equation works because we did it in B

let’s go on to the second equation

3(3) + 2(-7) ≤ -5

9 -14 ≤ -5

-5 ≤ -5

this works, so that means that both equations work and the whole thing works :)

5 0

3 years ago