What is the volume of this rectangular prisen?<br> Cm<br> 4 cm

6x+2y=12 how do I show my work

EleoNora [17]

Divide both sides
3x+y-6=0
move variable
6x=12-2y
divide
x=2-1/3y
solve
Final answer:
x=2

5 0

4 years ago

Read 2 more answers

Factor the expression y4 − 81 using the polynomial identity (x2 − y2) = (x − y)(x + y).

katrin [286]

The factored form is (y^2+9)(y^2-9).

Plug the two terms into the equation by finding the root of both.
√y^4= y^2
√81= 9

From here, you plug the terms into the form (x+y)(x-y)
(y^2+9)(y^2-9)

Hope this helps!

6 0

3 years ago

What is 80% of 230?

Orlov [11]

Answer:

184

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use the Statistical Applet: P ‑Value for a Test of One Proportion to answer the question.You have taken a sample of ????=1000 in

umka21 [38]

Answer:

$z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08$

$p_v =P(z>5.08)=1.88x10^{-7}$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .

Step-by-step explanation:

1) Data given and notation

n=20 represent the random sample taken

X=15 represent the people who eat breakfast

$\hat p=\frac{15}{20}=0.75$ estimated proportion of people who eat breakfast

$p_o=0.67$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 67%:

Null hypothesis: $p\leq 0.67$

Alternative hypothesis: $p > 0.67$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>5.08)=1.88x10^{-7}$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .

6 0

3 years ago

Solve the expression for x = 2. 6x + (-2x) + 2

garik1379 [7]

6(2)+(-2(2))
12+(-4)
12-4
8

3 0

3 years ago

What is the volume of this rectangular prisen? Cm 4 cm