Equation:
y + 2 = 1/3(x+1)
Assuming you are solving for Y:
y + 2 = 1/3(x) + 1/3(1)
(y + 2) - 2 = (1/3x + 1/3) - 2
y = 1/3x + 1/3 - 2
<u>y = 1/3x - 5/3</u>
Dy/dx=2x+2
So velocity will be zero when 2x+2=0, x=-1
Since d2y/dx2=2, it has a constant positive acceleration of 2, so that when dy/dx=0 it is at an absolute minimum value for f(x), which is also the vertex.
y(-1)=1-2+3=2
So the vertex is at (-1,2), which is an absolute minimum so the parabola opens upwards.
And by symmetry we can say that f(0)=f(-2)=3 so you have another two points that you can see (-2,3) and (0,3)
Answer:
I'm getting points
Step-by-step explanation:
so I can ask questionss
Answer:
let's use Pythagoras theorem,
h²=b²+l²
so,
ad²=ac²+dc²
6²=ac²+3²
36-9=ac²=27
√27 can be written as 3√3,
hence ac= 3√3
