Answer:
Area = 1250 square feet
Step-by-step explanation:
The formula for area of the bottom of the pool is given by:
Area = length× breadth
= 50 × 25
= 1250 square feet
Answer:
y = (-1/5)x + 23/5
Step-by-step explanation:
Given:
Two points;
(-2,5) and (3,4)
Find:
Equation of slope
Computation:
y = mx + b
5 = m(-2) + b
5 = -2m + b .......... Eq1
4 = m(3) + b
4 = 3m + b .......... Eq2
Eq2 - Eq1
-1 = 5m
m = -1/5
5 = -2m + b
5 = -2(-1/5) + b
5 = 2/5 + b
b = 23/5
y = mx + b
y = (-1/5)x + 23/5
2.) Given: There are 30 students. 24 are wearing sneakers.
Work: We can figure this out by finding the exact percentage of sneaker-wearers in the class.
To find the percentage, you do 24/30. 24/30 is equal to 80%.
Answer: Joe is wrong. The percentage of students wearing sneakers is 80% and not 70%.
3.) Given: There are 40 people total. 2 women per 3 men.
Work: 2:3 women to men
If we multiply both by 10, we will get 50 people in total.
20:30 = 50
So we need to shrivel this down to 40 by taking out 5 on both sides of the ratio.
50 - 5 - 5 = 15:25 = 40
But the ratio need to be divisible by 2 because of the 2 women that are needed per 3 men. We can do this by moving over one human to the men’s side.
There are 14 women and 26 men. I didn’t use any of the strategies there listed because I don’t even remember what those are. I’m in grade 9. I would say that the ratio table works best because I just used ratios...
4.) Given: Find simplified fraction of silicon. 100%.
Work: Add all things up to find out the denominator for the fraction. They will equal 100.
So the fraction is 28/100.
We can divide this fraction by 4.
7/25
This is the simplified form.
Answer: 7/25
Answer:
Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".
Part A
The definition of the Intersecting Secant-Tangent Theorem is:
"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."
This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".
Mathematically, it can be written as:
Part B
It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:
Thus,
Thus the length of TU=6 inches