Answer:
y =( -1/2 )x + 2
Step-by-step explanation:
first step is to determine the slope of the line ( which is the rise over the run) or symbolically slope is defined as m= ∆x / ∆y, so plugging those values we get...
m= ∆x / ∆y = (-1 - 0) / (4 - 2) = -1 / 2
so next is to find the zero( y-intercept) of the function by ....
y = mx + b
y = ( -1/2)x + b (since m is equal to -1/2)
2 = ( -1/2)0 + b
2= b
Answer:
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Answer:
(a)Revenue function,
Marginal Revenue function, R'(x)=580-2x
(b)Fixed cost =900
.
Marginal Cost Function=300+50x
(c)Profit,
(d)x=4
Step-by-step explanation:
<u>Part A
</u>
Price Function
The revenue function

The marginal revenue function

<u>Part B
</u>
<u>(Fixed Cost)</u>
The total cost function of the company is given by 
We expand the expression

Therefore, the fixed cost is 900
.
<u>
Marginal Cost Function</u>
If 
Marginal Cost Function, 
<u>Part C
</u>
<u>Profit Function
</u>
Profit=Revenue -Total cost

<u>
Part D
</u>
To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

The number of cakes that maximizes profit is 4.
1 x 10. It is unlikely that someone will run 103 meters in a second, along with 1010.
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.