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Dafna1 [17]
3 years ago
8

What number must you add to complete the square x^2+2x=9

Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0

Answer:

+ 1

Step-by-step explanation:

Given

x² + 2x = 9

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(1)x + 1² = 9 + 1²

(x + 1)² = 10

yaroslaw [1]3 years ago
3 0

Answer:x =(-2-√-32)/-2=1+2i√ 2 = 1.0000-2.8284i

x =(-2+√-32)/-2=1-2i√ 2 = 1.0000+2.8284

Step-by-step explanation:

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Write a system of linear equations for the graph below.
Vanyuwa [196]

Answer:

-3/-2

Step-by-step explanation:

because (x,y) the x coordinate is -3 and the y coordinate is -2

3 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
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Furkat [3]

Answer:

[13, 15, 17, 16, 12]

[16, 12, 17, 13, 15]

[16, 15, 14, 13, 12]

[17, 13, 15, 12, 14]

Step-by-step explanation:

Writing a Python code, I got the answers given, reading from left to right to down. For example, for [13, 15, 17, 16, 12], 13 is the top left circle, 15 is the middle right, 17 is the far right, 16 is the bottom left, and 12 is the bottom right

6 0
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strojnjashka [21]

Answer: (8)(-4.5)

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3 years ago
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quester [9]

Answer: Three plus Five equals Eight or 3= a · 5= 5a

Step-by-step explanation:

7 0
2 years ago
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