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Leni [432]
2 years ago
14

Need help Which one is it?

Mathematics
1 answer:
Sonbull [250]2 years ago
8 0
Use the app named connects works everytime
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Mr Suvillian is organizing items for the middle schools annual field trip. There are 8 classes at the school with 22 students in
Bas_tet [7]

Answer: 8 left over

Step-by-step explanation: Take 8 classes and multiply by 22 students each. Divide that answer by 12 to see what you have left over.

8x22=176

176/12= 14 remainder of 8

4 0
3 years ago
What is the solution for this system of equations? <br>y= -1/4x + 6<br>y= x+1​
snow_lady [41]

9514 1404 393

Answer:

  (x, y) = (4, 5)

Step-by-step explanation:

Equating the expressions for y gives ...

  -1/4x +6 = x +1

  5 = 5/4x . . . . . . . add 1/4x-1

  4 = x . . . . . . . . . . multiply by 4/5

  y = x +1 = 4 +1

  y = 5

The solution is (x, y) = (4, 5).

3 0
2 years ago
I need help with this . I don’t get how
Svetradugi [14.3K]
Simply collect like terms, numbers and or variables that have the same number and type of variable.

For example 15x^2 and 10x^2 are like terms. Circle the sign in front of the term to perform the correct operation.







5 0
2 years ago
Please help me on math
Eduardwww [97]

Answer:

45 inches

Step-by-step explanation:

85-40=45

b=45

how I know?

use the formula c^2-a^2=b^2

85 being c, a being 40 and b being 45

7 0
2 years ago
Read 2 more answers
An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.
SCORPION-xisa [38]

Answer:

(a)See below

(b)I) 0.125  (ii)0.828125   (iii)0.234375   (iv) 0.625   (v)0.65625

Step-by-step explanation:

When an  8-sided die is rolled twice, the sample space is the set of all possible pairs (a,b) where a is the 1st outcome and b is the 2nd outcome.

The sample space is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]

<u>PART A</u>

The sample space of the product a*b of each pair forms the required possibility diagram.

This is given as:  

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

<u>PART B</u>

I) A prime number

The number of products that gives prime numbers = 8  

The probability that the product is a prime number

=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125

ii) Not a perfect square  

Number of products that results in perfect squares =11

The probability that the product is not a perfect square

=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125

iii) A multiple of 5  

Number of products that are multiples of 5=15

 The probability that the product is a multiple of 5

=\dfrac{15}{64}\\=0.234375

iv) Less than or equal to 21

Number of products which are less than or equal to 21=40

 The probability that the product less than or equal to 21

=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625

v) Divisible by 4 or 6

Number of products divisible by 4 or 6= 42

 The probability that the product is divisible by 4 or 6

=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625

8 0
2 years ago
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