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nydimaria [60]
3 years ago
7

How do you answer this problem?: A shop sells one-pound bags of peanuts for $2 and three- pound bags for $5. If 9 bags are purch

ased for a total cost of $36, how many three-pound bags were purchased?
Mathematics
1 answer:
o-na [289]3 years ago
7 0
6 3-pound bags and 3 1-pound bags were bought
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Jason's dad gave him a budget of $150 to spend on lacrosse equipment. How much will Jason have left over if he buys a helmet for
Yanka [14]
The answer is 2.99 explanation is that I used my calculator lol
7 0
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Find the vertex.<br> f(x) = x2 + 3
Musya8 [376]

Answer:

(0,3)

Step-by-step explanation:

The parent function's vertex is at (0,0) and this function is being translated 3 units up, so the vertex is at (0,3)

4 0
3 years ago
 2 m³ of soil containing 35% sand was mixed into 6 m³ of soil containing 15% sand. What is the sand content of the mixture?
Alex17521 [72]
.2 m^3 is 10 percent
.2 m^3 is 10 percent
.2 m^3 is 10 percent
.1 m^3 is 5 percent
therefore
.7m^3 is 35%

.6m^3 is 10%
.3 m^3 is 5%
so .9m^3 is 15 %

all in .9m^3 +.7m^3 = 1.6 m^3 will be sand
6 0
3 years ago
Determine if the triangle with the given sides is acute, obtuse, or right. 36, 49, 60
kotykmax [81]
<span>When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:
</span>1) Square all 3 sides.
2) Sum the squares of the 2 shortest sides.
3) Compare this sum to the square of the 3rd side.

if sum > 3rd side²   Acute Triangle
if sum = 3rd side²   Right Triangle<span>
if sum < 3rd side²   Obtuse Triangle

1) 1,296   2,401   3,600
2) Sum = 3,697
3) </span><span>3,697 is greater than 3,600
Therefore, the triangle is acute.

Source:
http://www.1728.org/triantest.htm


</span>
4 0
3 years ago
Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points
SpyIntel [72]

Answer:

The length of diagonal XU is 6.40 units

Step-by-step explanation:

* Lets explain how to find the distance between two points

- The rule of the distance between two points (x_{1},y_{1})

 and (x_{2},y_{2}) is:

 d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

* Lets solve the problem

-From the attached figure:

- The coordinates of the vertex X are (2 , 2)

- The coordinates of the vertex U are (-2 , 7)

∴ The point (x_{1},y_{1}) = (2 , 2)

∴ The point (x_{2},y_{2}) = (-2 , 7)

∴ x_{1}=2,x_{2}=-2

∴  y_{1}=2,y_{2}=7

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∴ d=\sqrt{(-2-2)^{2}+(7-2)^{2}}=\sqrt{(-4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}

∵ \sqrt{41}=6.403124

∴ d = 6.40

* The length of diagonal XU is 6.40 units

6 0
3 years ago
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