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3 years ago

How to find the surface area of the open net

Mathematics

1 answer:

Kruka [31]3 years ago

5 0

To find the surface area of the open net, you’ll have to find the area of the faces
So, since there are 6 boxes you’ll have to find the area of the faces and add it up to find the surface area
10x4=40x4=160
3x4=12x2=24
160+24=184

Hope this helps ;)

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2/5 + 3/8 - Adding fractions

m_a_m_a [10]

Answer:31/40

Step-by-step explanation:

To add you have to have a common denominator. To get that you can multiply each fraction by one in different ways. 2/5 *8/8= 16/40 and 3/8* 5/5= 15/40 and then add those two to give you 31/40.

5 0

3 years ago

Read 2 more answers

Find the commission on a sale of $8,432 at 1 1/2% commission.

IrinaK [193]

Answer:

5621.33333333

Step-by-step explanation:

This is only the right answer if you are asking how much money 1 1/2 % of 8432 is.

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2 years ago

A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner

frozen [14]

Answer:

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner $I_{corner}$ is:

$I_{corner} = \int\limits \int\limits_R (x^2+y^2) \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx$

where :

(a and b are the length and the breath of the rectangle respectively )

$I_{corner} = \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx$

$I_{corner} = \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx$

$I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}$

$I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]$

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Thus; the moment of inertia of the lamina about one corner is $I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

7 0

3 years ago

Esma has a box that is 20 cm wide 10 cm high, and 10 cm deep she wants to fill the box with packages that are 5 cm wide 2 cm hig

anastassius [24]

Answer:

Esma can fit 3 packages in the box because 20+10+10=30 and 5+2+2=9 so if you add up 9 three times you get 27 and that is the closest number you can get before going over.

Step-by-step explanation:

6 0

2 years ago

If the graph of the linear equation ax-8y=15 has an x-intercept at (3,0), then what is the value of a?

mart [117]

Ax-8y=15
a(3)-8(0)=15
3a=15
a=5

4 0

3 years ago