Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
5 atm pressure must be applied to compress the gas to a volume of only 150.0 ml.
<h3>Given</h3>
Mass of oxygen at room temperature =500.0 ml
Volume of pressure = 50 atm pressure.
The gas to a volume = 150.0 ml
<h3>Explanation</h3>
The volume decreases by the factor = 500.0 mL / 150.0 mL
= 10 / 3
The pressure of the gas increased by a factor of 10/3 , which would make its final value equal to

= 5.00 atm
So, 5 atm pressure must be applied to compress the gas to a volume of only 150.0 ml.
Learn more about mass of oxygen here:
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