Answer:
So that oxidation of pyruvate can take place in mitochondria.
Explanation:
Pyruvates is produced in the glycolysis process which occurs in the cytoplasm. So pyruvate is produced in the cytoplasm of the cell. Pyruvate is produced by partial oxidation of glucose and to be fully oxidized it has to enter in the mitochondria.
So after entering the mitochondria the pyruvate first converts into acetyl CoA than this acetyl CoA enters in the citric acid cycle and fully oxidized into CO2. This oxidation generated NADP and FADH2 which provide reducing power during oxidative phosphorylation.
Answer:
the shape of protein is determined by its primary structure , amino acids . The sequence of amino acids in a protein is determined by the sequence of nucleotides
<span>Two checkpoints during the cell cycle that regulate cell division are right before S phase and M phase.
</span>Cell cycle checkpoints are control mechanisms <span>necessary for proper cell division. </span><span>In the cell cycle, there are two checkpoints: </span><span>the G1 checkpoint and the G2 checkpoint. <u>The G1 checkpoint is right before the S phase, and G2 checkpoint is right before the M phase.</u>
If something is wrong at the G1 checkpoint, the cell will not enter the cell cycle. It is important to be delayed before cell enters S phase where DNA replication commences.
The G2 checkpoint is a DNA damage checkpoint and if DNA is damaged, entering the cell cycle is delayed before mitosis (M phase).</span>
Answer:
Two gametes end up with 30 chromosomes, one gamete will have 31 and one will have 29.
Explanation:
During meiosis, a single diploid cell divides into four haploid cells with half the chromosome number than the parent cell.
During meiosis I, homologous chromosomes separate and the chromosome number in the two daughter cells goes down by half. During meiosis II, the "sister" chromatids separate, and the chromosome number in the respective daughter cells remains the same.
Non-disjunction of a single dyad in meiosis II causes that one of the daughter cells will have an extra chromosome, and another will be lacking one. The two other gametes will be normal.
I drew a simple example of what would happen during meiosis of a 2n=4 cell if there was non-disjunction in a single dyad during meiosis II.
