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3 years ago

The area and perimeter of parallelogram

Mathematics

1 answer:

adoni [48]3 years ago

6 0

Triangles ADE and CDF are similar, so:-
10/12 = 15/CD
CD = (12*15) / 10 = 18 cm = AB = base of the parallelogram

Area of the parallelogram = base * height = 18 *10 = 180 cm^2 (answer)

(b) The perimeter:-
AD = CB = 15 (opposite sides are equal)

Perimeter = 2*18 + 2*15 = 36 + 30 = 66 cm (answer)

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Answer:

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2 years ago

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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2 years ago

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Sergio039 [100]

Answer:

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3 years ago

Anyone know the answer??

Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

$x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

$x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54$

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1 year ago