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zimovet [89]
3 years ago
15

The area and perimeter of parallelogram

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Triangles ADE and CDF are similar,  so:-
10/12 = 15/CD
CD = (12*15) / 10 =  18 cm  = AB = base of the parallelogram

Area of the parallelogram = base * height = 18 *10 = 180  cm^2 (answer)

(b)  The perimeter:-
AD = CB = 15 (opposite sides are equal)

Perimeter = 2*18 + 2*15 = 36 + 30 = 66 cm (answer)

 
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1. Given ΔQRS (is congruent to) ΔTUV, QS = 3v + 2 and TV = 7v - 6, find the length of QS and TV. Provide a detailed response bel
Morgarella [4.7K]
Because ΔQRS is congruent to <span>ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6
</span><span>
</span><span>Work: 
</span>3v + 2 = 7v - 6
      +6          +6
3v + 8=7v
-3v       -3v
<u>8</u> = <span><u>4v</u>
</span>4      4
2 = v

3(2) + 2 = GS
6+2 = GS
8 = GS

7(2) - 6 = TV
14-6=TV
8 = TV

Final Answer: 8=QS and 8=TV

 
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Step-by-step explanation:

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