The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
The answer is 63 degrees.
Answer:
5 degrees
Step-by-step explanation:
Multiply the first equation by 4 (so that both equations will have 8x terms) and then subtract:
8x-20y = -24
8x +3y = 68
------------
0 -23y = -92
Now divide both sides by -23:
y = 4
Find x by plugging y=4 into either equation:
8x +3(4) = 68
8x = 68 - 12
8x = 56
x = 7
So the answer is ordered pair is (7,4)
