Answer:
The required confidence interval is (3.068,4.732)
Step-by-step explanation:
Consider the provided information.
He plans to use a 90% confidence interval. He surveys a random sample of 50 students. The sample mean is 3.90 alcoholic drinks per week. The sample standard deviation is 3.51 drinks and wants to construct 90% confidence interval.
Thus, n=50,
=3.90 σ=3.51
Now find degree of freedom.

The confidence level is 90% and df=49
Therefore,


Now by using t distribution table look at 49 df and alpha level on 0.05.

Calculate SE as shown:


Now multiply 1.67653 with 0.4964
Therefore, the marginal error is: 1.67653 × 0.4964≈ 0.832
Now add and subtract this value in given mean to find the confidence interval.

Hence, the required confidence interval is (3.068,4.732)
Answer:
The correct answer is B) 1555.6
Step-by-step explanation:
In order to find this, we must divide the part by the percentage. This will give us the total out of 100%
140/.09 = 1555.6
Answer:
Relationship is :linear
Rate of change : 3
Y-intercept : (0,1)
Equation that models the data : y=3x+1
Step-by-step explanation:
B and C
3^3 = 27
the cubed root of 27 is 3
Answer:
The correct answer is <u>B. 15 units</u>
Step-by-step explanation: