Answer:
x=1, y=8
Step-by-step explanation:
Plug y=8x into y=10x-4.
8x=10x-4
Subtract 10x from each side.
-2x=-2
Divide each side by -2.
x=1
Plug x=1 into y=8x.
y=8(1)
y=8
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Step-by-step explanation:
3y + 2x - 10 = 0
in standard form
2x + 3y -10=0
||
as (ax + by - c = 0)
m = -a/b
= -2/3
or
3y + 2x - 10 = 0
make y subject
y = -2/3x + 10/3
Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.
Step-by-step explanation:
Given function: 
The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.
i.e. 
Hence, f(x) will have vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.
So, the graph will horizontal asymptote at 
i.e. 
Hence, f(x) will have horizontal asymptote at y=3.
The simplest form of <span>20/8 is 5/2</span>
