Answer:
Therefore the correct option is 2. 35 degree.

Step-by-step explanation:
Consider an Isosceles Triangle, Δ ABC where,
∠BAC = 110°
TO Find:
∠ ABC = ∠ACB = ?
Solution:
For an Isosceles Triangle
Base Angles are equal
∴
Now,
Triangle sum property:
In a Triangle sum of the measures of all the angles of a triangle is 180°.

Therefore,

K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE


g is taken as 9.81
Answer:
we are always ready to help you
Answer:
9
Step-by-step explanation:
range is the range from the lowest # through the biggest # in other words subtract the smaller number from the bigger number