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Monica [59]
4 years ago
6

Find the value of x and the value of y for which (x,23) and (18,y) ate the points on the graph y=0.5x+15

Mathematics
1 answer:
shutvik [7]4 years ago
8 0

Answer:

x=16; y=24

Step-by-step explanation:

for (x,23), 23=0.5x+15

x=16

for (18xy), y=0.5*18+15=24

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Pre-Calc help:
stepladder [879]

Answer:

8x^2+8y^2-79x-32y+95=0

Step-by-step explanation:

Let the equation be : x^2+y^2+2gx+2fy+c=0

The point (1,1) must satisfy this equation.

1^2+1^2+2g*1+2f*1+c=0\\2g+2f+c=-2---(1)

Similarly, the point (1,3) must satisfy:

1^2+3^2+2g*1+2f*3+c=0\\1+9+2g+6f+c=0\\2g+6f+c=-10---(2)

Also for the point (9,2), we have:

9^2+2^2+2g*9+2f*2+c=0\\81+4+18g+4f+c=0\\18g+4f+c=-85---(3)

Solving the equations (1), (2) and (3) simultaneously, we get:

g=-\frac{-79}{16},f=-2,c=\frac{95}{8}

We Substitute this values to get:

x^2+y^2+2(\frac{-79}{16})x+2(-2)y+\frac{95}{8}=0

x^2+y^2-(\frac{79}{8})x-4y+\frac{95}{8}=0

Multiply through by 8 to get:

8x^2+8y^2-79x-32y+95=0

8 0
4 years ago
Write 38/15 as a mixed number
MrMuchimi
2 8/15 is the answer
7 0
3 years ago
Read 2 more answers
2(y + 5) <br> use the distributive property to expand expressions.
marta [7]

Answer:

2(y+5)

Step-by-step explanation:

= 2y+10 simple multiplication method

3 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!!
Leni [432]

Answer:

At the time of launch height of the object was 60 meters.

Step-by-step explanation:

An object was launched from a platform and its height was modeled by the function,

h(x) = -5x² + 20x + 60

Where x = time or duration after the launch

At the time of launch, x = 0

So, by putting x = 0 in this equation,

h(0) = -5×(0) + 20×(0) + 60

h(0) = 60

Therefore, at the time of launch height of the object was 60 meters.

4 0
3 years ago
The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the c
stealth61 [152]

Apply law of total resistance in parallel circuit

\\ \tt\hookrightarrow \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

\\ \tt\hookrightarrow \dfrac{1}{9+2J}=\dfrac{1}{3-5j}+\dfrac{1}{R_2}

\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{1}{9+2J}-\dfrac{1}{3-5J}

\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{3-5J-9-2J}{(9+2J)(3-5J)}

\\ \tt\hookrightarrow R_2=\dfrac{(9+2J)(3-5J)}{-6-7J}

4 0
3 years ago
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