Answer:
The next term is 13.
Step-by-step explanation:
Looking at the previous numbers...
for -7 to get to -3, you have to add 4, and for -3 to get to 1 you have to add 4.... and so on. So in order to find the next number, add 4 to 9, and which you get 13.
1.
2.
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3.
4.
Answer:
a = 50°, b = 130°, c = 20°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the 3 angles in the right triangle
a + 40° + 90° = 180°
a + 130° = 180° ( subtract 130° from both sides )
a = 50°
a and b are adjacent angles and sum to 180° , so
a + b = 180°
50° + b = 180° ( subtract 50° from both sides )
b = 130°
Then sum the angles in the top triangle, that is
30° + 130° + c = 180°
160° + c = 180° ( subtract 160° from both sides )
c = 20°
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
Answer:
Step-by-step explanation:
As it is given as ΔQRP and ΔARC are similar, so the ratio of their corresponding sides will be same.
So,
It is given as,
RC = 3.3
PR = 1.8
AC = 6.6
PQ = ??
Putting the values,
