All categories

2 years ago

An artist is making a mosaic using glass

Mathematics

1 answer:

Bond [772]2 years ago

4 0

Answer:

200

Step-by-step explanation:

Let x and 2x be the number of red tiles and blue tiles respectively.

x + 2x = 600

3x = 600

=> x = 200

No. of red tiles = 200

No. of blue tiles = 2(200) = 400

You might be interested in

£8.40 is shared equally between three brothers. How much does each brother receive?

alexandr1967 [171]

8.40/3 = £2.80 each
...............

7 0

2 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago

A) SSS<br> B) SAS<br> C) ASA<br> D) AAS

amm1812

This is B.SAS (side angle side)

4 0

3 years ago

When Nestor woke up, the temperature was - 5 C°. By noon, the temperature had increased by 9 C°.

Mars2501 [29]

Answer:

B hope this helps :)

Step-by-step explanation:

5 0

2 years ago

a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco

lina2011 [118]

$\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)$

The probability of drawing a red marble on the first attempt is

$\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35$

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event $R_1$ ). So

$\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27$

And so

$\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}$

4 0

3 years ago