2 heads and tails. time 5 times is 10. so 10 combos
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2} \\\\\\ center~(3,-7)\qquad radius=8](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B%7D%7B%20r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%28x-3%29%5E2%2B%28y%2B7%29%5E2%3D64%5Cimplies%20%5Bx-%5Cstackrel%7Bh%7D%7B3%7D%5D%5E2%2B%5By-%28%5Cstackrel%7Bk%7D%7B-7%7D%29%5D%5E2%3D%5Cstackrel%7Br%7D%7B8%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Acenter~%283%2C-7%29%5Cqquad%20radius%3D8)
so, the broadcast location and range is more or less like the picture below.
Answer:
The measure of <TRU is 72 deg.
Step-by-step explanation:
<QRU is a right angle, so it measures 90 deg.
Since m<QRT = 18 deg, then m<TRU must be 72 deg since 72 + 18 = 90.
Answer: The measure of <TRU is 72 deg.
Answer:
$10.25
Step-by-step explanation:
Set up a system of equations, so 3c + 2m = 7 and 2c + 4m = 8, where c = the cost of coffees, and m = cost of muffins
To solve multiply the first equation by -2(3c + 2m=7) so you get -6c -4m = -14 now add the two equations
-6c - 4m = -14
2c + 4m = 8 notice that -6c + 2c = -4c and -4m + 4m cancels, then -14+8=-6
so we have -4c = -6 so c = $1.50
To solve for m, substitute c = 1.50 so 3(1.50) + 2m = 7, so solve for m so
4.5 + 2m = 7, 2m = 2.5, so m = $1.25
So now solve the final problem 6(1.50) + 1(1.25) = $10.25
