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Arlecino [84]
3 years ago
9

A tin man has a head that is a cylinder with a cone on top. The height of the cylinder is 12 inches and the height of the cone i

s 6 inches. The radius of both the cylinder and the cone is 4 inches. What is the volume of the tin man's head in terms of pi?
Mathematics
1 answer:
boyakko [2]3 years ago
3 0
First find the volume of the cylinder, then the volume of the cone, and after you can add the two volumes.

Cylinder:
V = π r^2 h
h = 12 inches
r = 4 inches
V = π(4^2)(12)
V = 192π

Cone:
V = 1/3 π r^2 h
h = 6 inches
r = 4 inches
V = 1/3 π (4^2)(6)
V = 32π

Now adding the two volumes, 192π + 32π = 224π cubic inches
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On his vacation, Chad spent 1/8 of the day swimming, 1/6 of the day shopping, and 1/4 of the day water skiing. How much of the d
Anastaziya [24]

Answer:

11/24

Step-by-step explanation:

First find the common denominators of each fraction:

The common denominator of each fraction is 24

  • 1/8 multiplied by 3 is 3/24
  • 1/6 multiplied by 4 is 4/24
  • 1/4 multiplied my 6 is 6/24

add these fractions up

3/24 + 4/24 + 6/24 = 13/24

subtract 24/24 - 13/24 = 11/24

6 0
2 years ago
PLEASE HELP
sattari [20]
Square root of 89 = 9.43398113 rounded to the nearest hundredth is 9.43 :)
7 0
2 years ago
Read 2 more answers
Calculate the speed of an airplane that moves 50 meters in one second in both cm/s and km/s
zaharov [31]
This question is simply conversions

we know there are 100 cm in a m so..
50 × 100 = 5,000 cm/s

and we know there are 1,000 m in a know so..
50 ÷ 1,000 = 50/1,000 = 1/20 km/s
4 0
3 years ago
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
59:17
poizon [28]

Answer:-13,-25

Step-by-step explanation:

Save

Next

8 0
2 years ago
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