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3 years ago

Simplify. 2m2 – 4n2 3m – 6m2 – 2m 7n2

Mathematics

1 answer:

adelina 88 [10]3 years ago

4 0

The answer is A
hope this helped

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Simplify the sum. (8u^3+8u^2+6)+(4u^3-6u+3)

rewona [7]

Answer:

$\boxed{12u^3+8u^2-6u+9}$

Step-by-step explanation:

$(8u^3+8u^2+6)+(4u^3-6u+3) = 8u^3+8u^2+6+4u^3-6u+3$

Once

$8x+4x = 12x, \text{ as } x = u^3$

$8u^3+8u^2+6+4u^3-6u+3 = 12u^3+8u^2+6-6u+3 = \boxed{12u^3+8u^2-6u+9}$

You don't need to factor.

7 0

3 years ago

The output y and input x of a device are related by y = x + 1.4x3 . (a) Find the values of the output for steady-state operation

erma4kov [3.2K]

Answer:

a) $y(1) = 2.4$ , $y(2) = 13.2$ , b) $y(x) = 2.4 + 5.2\cdot (x-1)$ , $y(1) = 2.4$ , $y(2) = 7.6$

Step-by-step explanation:

a) The values of the output for steady-state operation are:

$y(1) = 1 + 1.4\cdot (1)^{3}$

$y(1) = 2.4$

$y(2) = 2 + 1.4\cdot (2)^{3}$

$y(2) = 13.2$

b) The formula for linearization is:

$y(x) = y(1) +\frac{dy}{dx}|_{x = 1} \cdot (x-1)$

The first derivative of the formula evaluated at x = 1 is:

$\frac{dy}{dx}|_{x=1} = 1 + 4.2\cdot (1)^{2}$

$\frac{dy}{dx}|_{x=1} = 5.2$

The linearized model is:

$y(x) = 2.4 + 5.2\cdot (x-1)$

The output at x = 2 is presented below:

$y(2) = 2.4 + 5.2\cdot (2-1)$

$y(2) = 7.6$

Linearized model offers reasonable approximations for small intervals.

5 0

3 years ago

Help me solve this problem. quick !!!<br> thank you!!!!!

pochemuha

I hope this helps you out with your question. (:
Just click on the photo and it'll show you.

6 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

zavuch27 [327]

A relation can be a function if an x value is not paired with more than y-values.
The x and y values are flipped when finding an inverse.

So, if in the inverse function a y value is paired with more than one x values, this will mean that in the function an x-value was paired with more than one y-values.

Looking at the graph we can say that no y-value in the inverse is paired with more than one x values, so the original relation would be a function.

So the answer is TRUE

4 0

3 years ago

Expresss 8 2/7 as a %

Darya [45]

828.57%

Step-by-step explanation:

8 0

3 years ago