1/4+6-2/3
3/12+72/12-8/12
75/12-8/12
67/12
or
.25+6-.66
6.25-.66
5.59
To solve this problem, we can set two equations.
Let x be the cost of coffee and y be the cost of latte.
Two coffees and one latte: 2x + y = 10.50
y=10.50 - 2x ...(1)
Three coffees and two lattes: 3x + 2y = 17.00...(2)
Put (1) into (2), we have:
3x + 2(10.50-2x) = 17.00
3x + 2(10.50) - 2(2x) = 17.00
3x + 21 - 4x = 17
Put the unknown to one side:
3x -4x = 17 - 21
-x = -4
When there are negative numbers on both sides, we can take the negative signs away:
x= 4
Therefore, cost of one coffee is A. $4.00.
Hope ot helps!
Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
Answer:
156?
Step-by-step explanation:
im not certan but isnt it just adding??
