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3 years ago

How does substitution help you to solve systems of equations?

1 answer:

5 0

In solving equations, each must have vales of x and y. X is any number and Y is the output of any number. If you substitute x for a number, you can solve the equation for y.

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HURRY! 1. The Junior Garden Club has $144 for their special project which is the planting of a flower garden near the high schoo

Ber [7]

For 144$ u can buy 36 rose stands and that’s it. Or with the 144$ u could buy 20 tulips

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3 years ago

The function is used to convert temperature from Celsius (C) to Fahrenheit (F). The function C(K) = K − 273.15 is used to conver

jeka94

Answer:

The correct function for converting temperature from Kelvin to Fahrenheit is $F(K) = \frac{9(K - 273.15)}{5} + 32$

Step-by-step explanation:

Kelvin to Celsius function:

The function to convert a temperature from degrees Kelvin to degrees Celsius is given by:

$C(K) = K - 273.15$

Celsius to Fahrenheit function:

The function to convert a temperature from degrees Celsius to degrees Fahrenheit is given by:

$F(C) = \frac{9C}{5} + 32$

Which is the correct function for converting temperature from Kelvin to Fahrenheit?

In the equation to find F(C), we use C = C(K). So

$F(C) = \frac{9C}{5} + 32$

$F(C(K)) = \frac{9(K - 273.15)}{5} + 32$

$F(K) = \frac{9(K - 273.15)}{5} + 32$

The correct function for converting temperature from Kelvin to Fahrenheit is $F(K) = \frac{9(K - 273.15)}{5} + 32$

8 0

3 years ago

99 POINTS!!

Jlenok [28]

The solution is -30 velocity

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4 years ago

Read 2 more answers

Approximate the sum of the convergent infinite series the least usingnumber of terms so that the error is less than .0001. What

____ [38]

Solution :

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ $a_n= \frac{(-1)^n}{n ! 2^n} \ \ \ \ \ a_{n+1}= \frac{(-1)^{n+1}}{(n+1) ! 2^{n+1}}$

Error = $|a_{n+1}|$

Error ≤ 0.0001

$|\frac{(-1)^{n+1}}{(n+1)!2^{n+1}}| \leq 0.0001$

$|\frac{1}{(n+1)!2^{n+1}}| \leq 10^{-4}$

$(n+1)! 2^{n+1} \geq 10000$

Now try, n ≥ 5

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\sum_{n=1 }^{5 } \frac{(-1)^n}{n ! 2^n}$ (with error 0.0001)

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\frac{-1}{1!2}+\frac{1}{2!2^2}-\frac{1}{3! 2^3}+\frac{1}{4! 2^4}-\frac{1}{5! 2^5}$

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = 0.6065104

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3 years ago

Help please I only have a few minutes left and I Lee’s to be fast super fast‼️❤️

SOVA2 [1]

Answer:

The discounted price is $109. So the bike now cost $218.

Step-by-step explanation:

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3 years ago