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juin [17]
3 years ago
14

How does substitution help you to solve systems of equations?

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
In solving equations, each must have vales of x and y. X is any number and Y is the output of any number. If you substitute x for a number, you can solve the equation for y. 
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Here are two offers for batteries.
trapecia [35]

OFFER A is cheaper.

Step-by-step explanation:

Given,

OFFER A

Pack of 5

£2.75

Pay for 3 packs get 1 free

And

OFFER A

Pack of 5

£2.75

Pay for 3 packs get 1 free

To find which offer is cheaper.

<u>For OFFER A</u>

For 4 Packets he needs to pay £2.75

He needs to buy 40 batteries.

He needs to buy 40÷(4×5) = 2 packets.

Total cost = £2.75 ×2 = £5.5

<u>For OFFER B</u>

For 4 Packets he needs to pay £2.52

He needs to buy 40 batteries.

He needs to buy 10 packets.

After discount he has to pay = £2.52 -(£2.52 ×\frac{1}{3}) = £1.68

Total cost = £1.68×10 = £16.8

Hence,

OFFER A is cheaper.

7 0
2 years ago
Write the equation of a line with slope 3 and y-intercept −3.
natta225 [31]
The equation would be y = 3x-3




4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP are similar isosceles triangles. What is the ratio of the sides? Using Complete sentences, explain how you coul
gregori [183]

Answer:

If an angle of 1 isosceles triangle is congruent to an angle of another isosceles triangle the triangles are similar. sometimes If the corresponding sides of 2 similar triangles are in a ratio of 3:4 then the there perimeters are in a ratio of 3:4. brainlist

Step-by-step explanation:

7 0
3 years ago
Romeo has captured many yellow-spotted.....
Harrizon [31]
I think c, parabolic
3 0
3 years ago
Read 2 more answers
Suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of
Lady_Fox [76]

Answer:

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 650 and a standard deviation of 24.

This means that \mu = 650, \sigma = 24.

Sample of 36:

This means that n = 36, s = \frac{24}{\sqrt{36}} = 4

What is the shape of the sampling distribution you would expect to produce?

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

7 0
2 years ago
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