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Vera_Pavlovna [14]
3 years ago
15

Write and equation in slope-intercept form of the line with slope -1/2 that contains the point (-4,-3)

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

y=-1/2x-5

Step-by-step explanation:

Well we know that the slope is -1/2 so we can write the equation like this:

y=-1/2x+b (This is because of y=mx+b) (m is slope) (b is y-intercept)

Now we can replace the y and x with -4 and -3 because of (x,y). (-4,-3) x is -4 and y is -3

-3=-1/2(-4)+b

-3=2+b

Subtract 2 on both side:

-2-3=2-2+b

-5=b

Answer:

y=-1/2x-5

Hope this helps!

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eimsori [14]
In this problem “like terms” has two groups: one with a number and y, and one with just numbers. First I’ll rewrite the equation with the terms in a different order, grouped with like terms. Then we’ll do the math for them:

7y + 10 + 3y - 4 - 6y

= 7y + 3y - 6y + 10 - 4

= 10y - 6y + 6

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Let me know if you have questions on this.
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3 years ago
Which table represent a linear function
777dan777 [17]

Answer:

The last answer is correct. (x: 1,2,3,4 ; y: -5,0,5,10)

Step-by-step explanation:

In a linear function, the rate of increase/decrease is constant (the same). For the last answer, since for every x increase, y increases by 5, it is linear and has a constant rate of change.

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Help asap!!! <br><br> exponential function matching table..?
masha68 [24]

Answer:

Step-by-step explanation:

Exponential equations have the form of a geometric sequence

y=ar^x\text{ y=final value, a=initial value, r=common ratio, x=term number}\\ \\ \text{The common ratio is found by dividing any term by the previous term, in this case}\\ \\ r=\frac{1}{3},\ a=27\\ \\ f(x)=27\left(\frac{1}{3}\right)^x

6 0
2 years ago
michelle bought the same fabric on 3 different occasions and recorded the data below what was the price per yard of fabric? answ
bazaltina [42]

Please consider the complete question.

Michelle bought the same fabric on 3 different occasions and recorded the data below.

Yards of Fabric         Total Cost

2.2                             $2.53

3.6                             $4.14

4.2                             $4.83

What was the price per yard of fabric?

To find the cost per yard of fabric, we will divide cost of yards by number of yards.

\text{Cost per yard}=\frac{\text{Cost}}{\text{Number of yards}}

\text{Cost per yard}=\frac{\$2.53}{2.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Let us find cost per yard using 2nd set of data.

\text{Cost per yard}=\frac{\$4.14}{3.6\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Similarly we will find cost per yard for 3rd set of data.

\text{Cost per yard}=\frac{\$4.83}{4.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Therefore, the cost per yard of fabric is $1.15.

4 0
3 years ago
The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.
S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 8, \sigma = 0.03

(a) Calculate P(7.99 ≤ X ≤ 8.01) when n = 16.

n = 16, so s = \frac{0.03}{4} = 0.0075

This probability is the pvalue of Z when X = 8.01 subtracted by the pvalue of Z when X = 7.99. So

X = 8.01

Z = \frac{X - \mu}{\sigma}

Applying the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.0075}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 7.99

Z = \frac{X - \mu}{s}

Z = \frac{7.99 - 8}{0.0075}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918

0.9082 - 0.0918 = 0.8164

P(7.99 ≤ X ≤ 8.01) = 0.8164

(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 25? P(X ≥ 8.01) =

n = 25, so s = \frac{0.03}{5} = 0.006

This is 1 subtracted by the pvalue of Z when X = 8.01. So

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.006}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

P(X ≥ 8.01) = 0.0475.

4 0
3 years ago
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