Let us say
The Height from which the ball was first dropped as H0 = 248 feet
The Height reached by the ball after second bounce is H1
The Height reached by the ball after second bounce is H2 = 62 feet
Given , Height the ball reaches after bounce is a fraction of the height the ball reached in the previous bounce
The Height reached by the ball after second bounce = H2 = X of H1
==> 62 = X * H1 ...................Equation 1
The Height reached by the ball after first bounce = H1 = X of H0
==> H1 = X * 248 ...................Equation 2
Substituting value of H1 from Equation 2 to Equation 1
62 = X * H1 = X * X * 248
X^2 = 62/248 = 31/124 = 1/4
X = 1/2
Answer is A. 1/2
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<h2>Ayushi Singh Animation</h2>
Answer:
4.5
miles
Step-by-step explanation:
Well, he runs
3
miles in
28
minutes. Also, see that
42
=
28
⋅
1.5
.
So, his journey would just be running
1.5
times, with each time running
28
minutes.
So, he runs a total of
1.5
⋅
3
=
4.5
miles
Answer:
see explanation
Step-by-step explanation:
For the ellipse
+ = 1
Then the vertices are (a, 0), (- a, 0) and (0, b), (0, - b)
Given
+ = 1
Then
a² = 4 ⇒ a = 2 and b² = 100 ⇒ b = 10
Hence the vertices are
(2, 0), (- 2, 0) and (0, 10), (0, - 10)
Based on the characteristics of the distribution, the probability that the first goal is scored in less than 4 minutes is 0.
<h3>What is the probability?</h3>
For us to be able to calculate the probability that the first goal is scored in less than 4 minutes, the distribution needs to satisfy the requirements of the Central Limit Theorem(CLT).
Based on the fact that the distribution here is extremely right skewed, then it does not satisfy the requirements of CLT so the probability is 0.
First part of question:
The distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right skewed with population mean 12 minutes and population standard deviation 8 minutes.
Find out more on the requirements of the Central Limit Theorem at brainly.com/question/18403552
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Answer:
Step-by-step explanation:
A = 2(½(20)(15)) + 16(15 + 20 + 25) = 1,260 in²