Answer:
<h2>no real solution</h2>
Step-by-step explanation:
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
As you must know, If one root of the polynomial 7-√5, the other will be 7+√5 i.e irrational root occur in pairs.
A polynomial function cannot have single unreal i.e irrational root. It always occur in pairs.
So , consider a polynomial function of any degree, if it has a root 7-√5, then it must have another root as 7+√5.
A polynomial can't have 7-√5 as a single root.
Answer:
n= -9
Step-by-step explanation:
-3 ( n+5 ) = 12
-3n - 15 = 12
-3n = 12+15
-3n = 27
n = -27/3
n = -9
<span>The correct answer is 1 16/25.
Explanation<span>:
This is read as "one and sixty-four one-hundredths." This means the fraction would be 1 64/100.
Both numerator and denominator are even, so we will divide both by 2 and get 1 32/50.
Again, both are even, so we divide by 2 again and get 1 16/25.</span></span>
